(x^2-5)(x^2-4x+5)=0

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Solution for (x^2-5)(x^2-4x+5)=0 equation: 


Simplifying
(x2 + -5)(x2 + -4x + 5) = 0

Reorder the terms:
(-5 + x2)(x2 + -4x + 5) = 0

Reorder the terms:
(-5 + x2)(5 + -4x + x2) = 0

Multiply (-5 + x2) * (5 + -4x + x2)
(-5(5 + -4x + x2) + x2(5 + -4x + x2)) = 0
((5 * -5 + -4x * -5 + x2 * -5) + x2(5 + -4x + x2)) = 0
((-25 + 20x + -5x2) + x2(5 + -4x + x2)) = 0
(-25 + 20x + -5x2 + (5 * x2 + -4x * x2 + x2 * x2)) = 0
(-25 + 20x + -5x2 + (5x2 + -4x3 + x4)) = 0

Combine like terms: -5x2 + 5x2 = 0
(-25 + 20x + 0 + -4x3 + x4) = 0
(-25 + 20x + -4x3 + x4) = 0

Solving
-25 + 20x + -4x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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